Tuesday, April 8, 2008
Tuesday, April 1, 2008
Wednesday, March 26, 2008
Quadrialteral Properties
Quadrilateral - 4 sided polygon
A. Kite -
1. has consecutive sides congruent but opposite sides are not.
2. the diagonals are perpendicular
3. has exactly one pair of opposite angles congruent.
B. Trapezoid -
1. Has exactly one pair of opposite sides parallel
C. Isosceles Trapezoid -
1. Has exactly one pair of opposite sides parallel
2. the non-parallel sides are congruent (legs congruent)
3. the diagonals are congruent
4. the base angles are congruent
D. Parallelogram -
1. Definition: has both pairs of opposite sides parallel
2. has both pairs of opposite sides congruent
3. has one pair of opposite sides parallel and congruent
4. has both pairs of opposite angles congruent
5. has consecutive angles supplementary
6. the diagonals bisect each other
7. the diagonals divide the parallelogram into 2 congruent triangles
E. Rhombus -
1. All of the properties of a parallelogram
2. All sides are congruent (equilateral)
3. diagonals are perpendicular
4. diagonals bisect opposite angles
F. Rectangle -
1. All of the properties of a parallelogram
2. all angles are congruent (equiangular)
3. diagonals are congruent
G. Square -
1. All the properties of a parallelogram, rhombus and rectangle
check out this website:
http://regentsprep.org/Regents/math/quad/LQuad.htm
Coordinate Geometry
check out this website:
http://regentsprep.org/Regents/mathb/1D/Coordinatelesson.htm
Pythagorean Theorem which is:
c2 = a2 + b2
since a = (x2 – x1) and b = (y2 – y1)
we get
c2 = (x2 – x1)2 + (y2 – y1)2
so taking the square root of both sides we have our distance formula.

Using the following chart, if we have to prove congruent segments, we have to show they have equal length by using the distance formula.
Monday, February 25, 2008
Geometry Proofs - unit 2 Triangles
1. Δ ABC is congruent to Δ ABC , this is by the Reflexive Postulate
2. if Δ ABC is congruent to Δ DEF then Δ DEF is congruent to Δ ABC, this is by the Symmetric Postulate
3. if Δ ABC is congruent to Δ DEF and Δ DEF is congruent to Δ GHI, Then Δ ABC is congruent to Δ GHI by the Transitivity Postulate
5 ways to show Triangle Congruence:
1. SAS = SAS Congruence Postulate - if two sides and the included angle of one triangle are congruent to two sides and the included angle of a second triangle, then the two triangles are congruent.
Example: Given ΔABC and ΔDEF,
if AB = DE, BC = EF and angle B = angle E, then ΔABC = ΔDEF.
2. SSS = SSS Congruence Postulate - if three sides of one triangle are congruent to three sides of a second triangle, then the two triangles are congruent.
Example: Given ΔABC and ΔDEF,
if AB = DE, BC = EF and AC = DF, then ΔABC = ΔDEF.
3. ASA = ASA Congruence Postulate - if two angles and the included side of one triangle are congruent to two angles and the included side of a second triangle, then the two triangles are congruent.
Example: Given ΔABC and ΔDEF,
if angle A = angle D, AB = DE, and angle B = angle E, then Δ ABC = Δ DEF.
4. AAS = AAS Congruence Postulate - if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of a second triangle, then the two triangles are congruent.
Example: Given Δ ABC and Δ DEF,
if angle A = angle D, angle C = angle F, and BC = EF , then Δ ABC = Δ DEF.
5. HL = HL Congruence Postulate - if the leg and hypotenuse of one right triangle is congruent to the corresponding leg and hypotenuse of another right triangle, then the two triangles are congruent by hypotenuse - leg postulate.
Example: Given right Δ ABC and right Δ DEF, if angle B and angle E are both right angles and leg AB = leg DE and hypotenuse AC = hypotenuse DF, then Δ ABC = Δ DEF.
I) Vocabulary:
A) When two figures are congruent, there is a correspondence between their angles and sides such that corresponding angles are congruent and corresponding sides are congruent.
Example: Given Δ ABC is congruent to Δ PQR then we know
1) angle A = angle P, angle B = angle Q, and angle C = angle R
2) AB = PQ, BC = QR, and AC = PR By Corresponding Parts of Congruent Triangles are Congruent (CPCTC) - which means that if 2 triangles are congruent, then their corresponding parts are congruent
Make sure that you list the corresponding angles in the same order with the triangle congruence.
Example: ΔABC = ΔDEF is not the same as ΔABC = ΔEFD because
ΔABC = ΔDEF has angle A = angle D, angle B = angle E and angle C = angle F
while ΔABC = ΔEFD has angle A = angle E, angle B = angle F and angle C = angle D
B) Third Angles Theorem - if two angles of one triangle are congruent to two angles of another triangle, then the third angles are also congruent.
C) Reflexive Postulate - Every triangle is congruent to itself
D) Symmetric Postulate - If ΔABC = ΔDEF, then ΔDEF = ΔABC
E) Transitive Postulate - If ΔABC = ΔDEF and ΔDEF = ΔJKL, then ΔABC = ΔJKL
Theorems to remember:
If 2 angles of one triangle are congruent then the sides opposite are congruent.
If 2 sides of one triangle are congruent then the angles opposite are congruent.
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Practice Proofs:
Friday, February 15, 2008
Precalculus Unit 8 - chapter 6.3, 6.4, 10.5, 10.6, 10.7
Unit 8
Vectors and Parametric/Polar Equations
Section 6.3A HW# 53; Pg.453; #1 – 45 by 4’s (1, 5, 9, …)
Section 6.3B; HW # 54; *Pg.453; #3, 11, 19, 23, 31, 39, 43
Pg.454; #49, 53, 57, 61, 65, 69, 73, 74, 82
Section 6.4; HW # 55; *Pg. 454; #51, 55, 59, 63, 67, 71,
Pg. 464; #1, 5, 9, 13, 17, 21, 25, 29, 33, 37
Quiz on Sections 6.3A – 6.3B Next Class
Section 10.5; HW# 56; *Pg.464; #3, 7, 11, 15, 19, 23, 27, 31
Pg.736; #1, 5, 9, 13, 21, 29, 41, 47
Section 10.6; HW# 57; *Pg.736; #3, 7, 11, 17, 27, 43
Pg.743; #5 – 41 by 4’s, 45, 50, 53 – 57 odds
Quiz on Sections 6.4 – 10.5 Next Class
Section 10.7; HW# 58; *Pg.743; #7, 11, 15, 23, 27, 39, 47, 59
Pg.752; #21 – 33 odds, 55, 59
Review HW #59
Pg.480; 39, 43, 47, 51, 59, 69, 79, 83, 85
Pg.762; 47, 49, 59, 65, 69, 73, 75, 81, 85, 89
HW #60; Unit 8 Test
Tuesday, February 5, 2008
Unit One for Proofs - Angles and Lines
As you can see, in step 2, we added equal quantities to each other. This is Addition Postulate.